2(y-4)+8=1/2(6y+20)

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Solution for 2(y-4)+8=1/2(6y+20) equation: 



2(y-4)+8=1/2(6y+20)

We move all terms to the left:

2(y-4)+8-(1/2(6y+20))=0



Domain of the equation: 2(6y+20))!=0

y∈R



We multiply parentheses

2y-(1/2(6y+20))-8+8=0

We multiply all the terms by the denominator


2y*2(6y+20))-(1-8*2(6y+20))+8*2(6y+20))=0

We add all the numbers together, and all the variables

2y*2(6y+20))-(1-8*2(6y+20))+8*2(6y=0

Wy multiply elements

4y^2(6-32y^2(6=0

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