2(y-4)-2=y+y-7-3

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Solution for 2(y-4)-2=y+y-7-3 equation: 



2(y-4)-2=y+y-7-3

We move all terms to the left:

2(y-4)-2-(y+y-7-3)=0

We add all the numbers together, and all the variables

2(y-4)-(2y-10)-2=0

We multiply parentheses

2y-(2y-10)-8-2=0

We get rid of parentheses

2y-2y+10-8-2=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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