2(y-4)-3=-2(-6y+7)-y

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Solution for 2(y-4)-3=-2(-6y+7)-y equation: 



2(y-4)-3=-2(-6y+7)-y

We move all terms to the left:

2(y-4)-3-(-2(-6y+7)-y)=0

We multiply parentheses

2y-(-2(-6y+7)-y)-8-3=0



We calculate terms in parentheses: -(-2(-6y+7)-y), so:

-2(-6y+7)-y

We add all the numbers together, and all the variables

-1y-2(-6y+7)

We multiply parentheses

-1y+12y-14

We add all the numbers together, and all the variables

11y-14

Back to the equation:

-(11y-14)



We add all the numbers together, and all the variables

2y-(11y-14)-11=0

We get rid of parentheses

2y-11y+14-11=0

We add all the numbers together, and all the variables

-9y+3=0

We move all terms containing y to the left, all other terms to the right

-9y=-3

y=-3/-9

y=1/3

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