2(y-4)-4y=12

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Solution for 2(y-4)-4y=12 equation: 



2(y-4)-4y=12

We move all terms to the left:

2(y-4)-4y-(12)=0

We add all the numbers together, and all the variables

-4y+2(y-4)-12=0

We multiply parentheses

-4y+2y-8-12=0

We add all the numbers together, and all the variables

-2y-20=0

We move all terms containing y to the left, all other terms to the right

-2y=20

y=20/-2

y=-10

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