2(y-4)-6y=12

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Solution for 2(y-4)-6y=12 equation:



2(y-4)-6y=12
We move all terms to the left:
2(y-4)-6y-(12)=0
We add all the numbers together, and all the variables
-6y+2(y-4)-12=0
We multiply parentheses
-6y+2y-8-12=0
We add all the numbers together, and all the variables
-4y-20=0
We move all terms containing y to the left, all other terms to the right
-4y=20
y=20/-4
y=-5

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