2(y-4)-8=-3(-4y+8)-4y

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Solution for 2(y-4)-8=-3(-4y+8)-4y equation:



2(y-4)-8=-3(-4y+8)-4y
We move all terms to the left:
2(y-4)-8-(-3(-4y+8)-4y)=0
We multiply parentheses
2y-(-3(-4y+8)-4y)-8-8=0
We calculate terms in parentheses: -(-3(-4y+8)-4y), so:
-3(-4y+8)-4y
We add all the numbers together, and all the variables
-4y-3(-4y+8)
We multiply parentheses
-4y+12y-24
We add all the numbers together, and all the variables
8y-24
Back to the equation:
-(8y-24)
We add all the numbers together, and all the variables
2y-(8y-24)-16=0
We get rid of parentheses
2y-8y+24-16=0
We add all the numbers together, and all the variables
-6y+8=0
We move all terms containing y to the left, all other terms to the right
-6y=-8
y=-8/-6
y=1+1/3

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