2(y-4)=-3(2y+1)

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Solution for 2(y-4)=-3(2y+1) equation: 



2(y-4)=-3(2y+1)

We move all terms to the left:

2(y-4)-(-3(2y+1))=0

We multiply parentheses

2y-(-3(2y+1))-8=0



We calculate terms in parentheses: -(-3(2y+1)), so:

-3(2y+1)

We multiply parentheses

-6y-3

Back to the equation:

-(-6y-3)



We get rid of parentheses

2y+6y+3-8=0

We add all the numbers together, and all the variables

8y-5=0

We move all terms containing y to the left, all other terms to the right

8y=5

y=5/8

y=5/8

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