2(y-4)=-4(y-8)

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Solution for 2(y-4)=-4(y-8) equation: 



2(y-4)=-4(y-8)

We move all terms to the left:

2(y-4)-(-4(y-8))=0

We multiply parentheses

2y-(-4(y-8))-8=0



We calculate terms in parentheses: -(-4(y-8)), so:

-4(y-8)

We multiply parentheses

-4y+32

Back to the equation:

-(-4y+32)



We get rid of parentheses

2y+4y-32-8=0

We add all the numbers together, and all the variables

6y-40=0

We move all terms containing y to the left, all other terms to the right

6y=40

y=40/6

y=6+2/3

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