2(y-4)=-4y-32

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Solution for 2(y-4)=-4y-32 equation: 



2(y-4)=-4y-32

We move all terms to the left:

2(y-4)-(-4y-32)=0

We multiply parentheses

2y-(-4y-32)-8=0

We get rid of parentheses

2y+4y+32-8=0

We add all the numbers together, and all the variables

6y+24=0

We move all terms containing y to the left, all other terms to the right

6y=-24

y=-24/6

y=-4

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