2(y-4)=16,y=

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Solution for 2(y-4)=16,y= equation: 



2(y-4)=16.y=

We move all terms to the left:

2(y-4)-(16.y)=0

We add all the numbers together, and all the variables

2(y-4)-(+16.y)=0

We multiply parentheses

2y-(+16.y)-8=0

We get rid of parentheses

2y-16.y-8=0

We add all the numbers together, and all the variables

-14y-8=0

We move all terms containing y to the left, all other terms to the right

-14y=8

y=8/-14

y=-4/7

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