2(y-4)=2y+2-4(-3y-1)

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Solution for 2(y-4)=2y+2-4(-3y-1) equation: 



2(y-4)=2y+2-4(-3y-1)

We move all terms to the left:

2(y-4)-(2y+2-4(-3y-1))=0

We multiply parentheses

2y-(2y+2-4(-3y-1))-8=0



We calculate terms in parentheses: -(2y+2-4(-3y-1)), so:

2y+2-4(-3y-1)

determiningTheFunctionDomain
2y-4(-3y-1)+2

We multiply parentheses

2y+12y+4+2

We add all the numbers together, and all the variables

14y+6

Back to the equation:

-(14y+6)



We get rid of parentheses

2y-14y-6-8=0

We add all the numbers together, and all the variables

-12y-14=0

We move all terms containing y to the left, all other terms to the right

-12y=14

y=14/-12

y=-1+1/6

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