2(y-4)=3(2y-1)

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Solution for 2(y-4)=3(2y-1) equation:



2(y-4)=3(2y-1)
We move all terms to the left:
2(y-4)-(3(2y-1))=0
We multiply parentheses
2y-(3(2y-1))-8=0
We calculate terms in parentheses: -(3(2y-1)), so:
3(2y-1)
We multiply parentheses
6y-3
Back to the equation:
-(6y-3)
We get rid of parentheses
2y-6y+3-8=0
We add all the numbers together, and all the variables
-4y-5=0
We move all terms containing y to the left, all other terms to the right
-4y=5
y=5/-4
y=-1+1/4

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