2(y-4)=3-(3y+1)

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Solution for 2(y-4)=3-(3y+1) equation: 



2(y-4)=3-(3y+1)

We move all terms to the left:

2(y-4)-(3-(3y+1))=0

We multiply parentheses

2y-(3-(3y+1))-8=0



We calculate terms in parentheses: -(3-(3y+1)), so:

3-(3y+1)

determiningTheFunctionDomain
-(3y+1)+3

We get rid of parentheses

-3y-1+3

We add all the numbers together, and all the variables

-3y+2

Back to the equation:

-(-3y+2)



We get rid of parentheses

2y+3y-2-8=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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