2(y-4)=4y-(2y+4)

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Solution for 2(y-4)=4y-(2y+4) equation: 



2(y-4)=4y-(2y+4)

We move all terms to the left:

2(y-4)-(4y-(2y+4))=0

We multiply parentheses

2y-(4y-(2y+4))-8=0



We calculate terms in parentheses: -(4y-(2y+4)), so:

4y-(2y+4)

We get rid of parentheses

4y-2y-4

We add all the numbers together, and all the variables

2y-4

Back to the equation:

-(2y-4)



We get rid of parentheses

2y-2y+4-8=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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