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2(y-4)=5(y-4)
We move all terms to the left:
2(y-4)-(5(y-4))=0
We multiply parentheses
2y-(5(y-4))-8=0
We calculate terms in parentheses: -(5(y-4)), so:We get rid of parentheses
5(y-4)
We multiply parentheses
5y-20
Back to the equation:
-(5y-20)
2y-5y+20-8=0
We add all the numbers together, and all the variables
-3y+12=0
We move all terms containing y to the left, all other terms to the right
-3y=-12
y=-12/-3
y=+4
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