2(y-4)=8y+28

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Solution for 2(y-4)=8y+28 equation: 



2(y-4)=8y+28

We move all terms to the left:

2(y-4)-(8y+28)=0

We multiply parentheses

2y-(8y+28)-8=0

We get rid of parentheses

2y-8y-28-8=0

We add all the numbers together, and all the variables

-6y-36=0

We move all terms containing y to the left, all other terms to the right

-6y=36

y=36/-6

y=-6

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