2(y-4)=y+2-2(-7y-2)

Solution for 2(y-4)=y+2-2(-7y-2) equation:

2(y-4)=y+2-2(-7y-2)

We move all terms to the left:

2(y-4)-(y+2-2(-7y-2))=0

We multiply parentheses

2y-(y+2-2(-7y-2))-8=0


We calculate terms in parentheses: -(y+2-2(-7y-2)), so:

y+2-2(-7y-2)

determiningTheFunctionDomain
y-2(-7y-2)+2

We multiply parentheses

y+14y+4+2

We add all the numbers together, and all the variables

15y+6

Back to the equation:

-(15y+6)


We get rid of parentheses

2y-15y-6-8=0

We add all the numbers together, and all the variables

-13y-14=0

We move all terms containing y to the left, all other terms to the right

-13y=14

y=14/-13

y=-1+1/13