2(y-5)+3y=y+6

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Solution for 2(y-5)+3y=y+6 equation: 



2(y-5)+3y=y+6

We move all terms to the left:

2(y-5)+3y-(y+6)=0

We add all the numbers together, and all the variables

3y+2(y-5)-(y+6)=0

We multiply parentheses

3y+2y-(y+6)-10=0

We get rid of parentheses

3y+2y-y-6-10=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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