2(y-5)+4=3(y+2)-5

Solution for 2(y-5)+4=3(y+2)-5 equation:

2(y-5)+4=3(y+2)-5

We move all terms to the left:

2(y-5)+4-(3(y+2)-5)=0

We multiply parentheses

2y-(3(y+2)-5)-10+4=0


We calculate terms in parentheses: -(3(y+2)-5), so:

3(y+2)-5

We multiply parentheses

3y+6-5

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)


We add all the numbers together, and all the variables

2y-(3y+1)-6=0

We get rid of parentheses

2y-3y-1-6=0

We add all the numbers together, and all the variables

-1y-7=0

We move all terms containing y to the left, all other terms to the right

-y=7

y=7/-1

y=-7