2(y-5)-2=-2(-8y+2)-4y

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Solution for 2(y-5)-2=-2(-8y+2)-4y equation: 



2(y-5)-2=-2(-8y+2)-4y

We move all terms to the left:

2(y-5)-2-(-2(-8y+2)-4y)=0

We multiply parentheses

2y-(-2(-8y+2)-4y)-10-2=0



We calculate terms in parentheses: -(-2(-8y+2)-4y), so:

-2(-8y+2)-4y

We add all the numbers together, and all the variables

-4y-2(-8y+2)

We multiply parentheses

-4y+16y-4

We add all the numbers together, and all the variables

12y-4

Back to the equation:

-(12y-4)



We add all the numbers together, and all the variables

2y-(12y-4)-12=0

We get rid of parentheses

2y-12y+4-12=0

We add all the numbers together, and all the variables

-10y-8=0

We move all terms containing y to the left, all other terms to the right

-10y=8

y=8/-10

y=-4/5

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