2(y-5)-5=-3(-7y+1)-4y

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Solution for 2(y-5)-5=-3(-7y+1)-4y equation: 



2(y-5)-5=-3(-7y+1)-4y

We move all terms to the left:

2(y-5)-5-(-3(-7y+1)-4y)=0

We multiply parentheses

2y-(-3(-7y+1)-4y)-10-5=0



We calculate terms in parentheses: -(-3(-7y+1)-4y), so:

-3(-7y+1)-4y

We add all the numbers together, and all the variables

-4y-3(-7y+1)

We multiply parentheses

-4y+21y-3

We add all the numbers together, and all the variables

17y-3

Back to the equation:

-(17y-3)



We add all the numbers together, and all the variables

2y-(17y-3)-15=0

We get rid of parentheses

2y-17y+3-15=0

We add all the numbers together, and all the variables

-15y-12=0

We move all terms containing y to the left, all other terms to the right

-15y=12

y=12/-15

y=-4/5

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