2(y-5)-8=-6(-4y+1)-8y

Solution for 2(y-5)-8=-6(-4y+1)-8y equation:

2(y-5)-8=-6(-4y+1)-8y

We move all terms to the left:

2(y-5)-8-(-6(-4y+1)-8y)=0

We multiply parentheses

2y-(-6(-4y+1)-8y)-10-8=0


We calculate terms in parentheses: -(-6(-4y+1)-8y), so:

-6(-4y+1)-8y

We add all the numbers together, and all the variables

-8y-6(-4y+1)

We multiply parentheses

-8y+24y-6

We add all the numbers together, and all the variables

16y-6

Back to the equation:

-(16y-6)


We add all the numbers together, and all the variables

2y-(16y-6)-18=0

We get rid of parentheses

2y-16y+6-18=0

We add all the numbers together, and all the variables

-14y-12=0

We move all terms containing y to the left, all other terms to the right

-14y=12

y=12/-14

y=-6/7