2(y-5)=2y+3-2(-5y-1)

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Solution for 2(y-5)=2y+3-2(-5y-1) equation: 



2(y-5)=2y+3-2(-5y-1)

We move all terms to the left:

2(y-5)-(2y+3-2(-5y-1))=0

We multiply parentheses

2y-(2y+3-2(-5y-1))-10=0



We calculate terms in parentheses: -(2y+3-2(-5y-1)), so:

2y+3-2(-5y-1)

determiningTheFunctionDomain
2y-2(-5y-1)+3

We multiply parentheses

2y+10y+2+3

We add all the numbers together, and all the variables

12y+5

Back to the equation:

-(12y+5)



We get rid of parentheses

2y-12y-5-10=0

We add all the numbers together, and all the variables

-10y-15=0

We move all terms containing y to the left, all other terms to the right

-10y=15

y=15/-10

y=-1+1/2

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