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2(y-5)=2y+3-2(-5y-1)
We move all terms to the left:
2(y-5)-(2y+3-2(-5y-1))=0
We multiply parentheses
2y-(2y+3-2(-5y-1))-10=0
We calculate terms in parentheses: -(2y+3-2(-5y-1)), so:We get rid of parentheses
2y+3-2(-5y-1)
determiningTheFunctionDomain 2y-2(-5y-1)+3
We multiply parentheses
2y+10y+2+3
We add all the numbers together, and all the variables
12y+5
Back to the equation:
-(12y+5)
2y-12y-5-10=0
We add all the numbers together, and all the variables
-10y-15=0
We move all terms containing y to the left, all other terms to the right
-10y=15
y=15/-10
y=-1+1/2
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