2(y-5)=3y-22

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Solution for 2(y-5)=3y-22 equation: 



2(y-5)=3y-22

We move all terms to the left:

2(y-5)-(3y-22)=0

We multiply parentheses

2y-(3y-22)-10=0

We get rid of parentheses

2y-3y+22-10=0

We add all the numbers together, and all the variables

-1y+12=0

We move all terms containing y to the left, all other terms to the right

-y=-12

y=-12/-1

y=+12

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