2(y-5)=4(2-y)

Solution for 2(y-5)=4(2-y) equation:

2(y-5)=4(2-y)

We move all terms to the left:

2(y-5)-(4(2-y))=0

We add all the numbers together, and all the variables

2(y-5)-(4(-1y+2))=0

We multiply parentheses

2y-(4(-1y+2))-10=0


We calculate terms in parentheses: -(4(-1y+2)), so:

4(-1y+2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)


We get rid of parentheses

2y+4y-8-10=0

We add all the numbers together, and all the variables

6y-18=0

We move all terms containing y to the left, all other terms to the right

6y=18

y=18/6

y=3