2(y-5)=7(y+4)

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Solution for 2(y-5)=7(y+4) equation: 



2(y-5)=7(y+4)

We move all terms to the left:

2(y-5)-(7(y+4))=0

We multiply parentheses

2y-(7(y+4))-10=0



We calculate terms in parentheses: -(7(y+4)), so:

7(y+4)

We multiply parentheses

7y+28

Back to the equation:

-(7y+28)



We get rid of parentheses

2y-7y-28-10=0

We add all the numbers together, and all the variables

-5y-38=0

We move all terms containing y to the left, all other terms to the right

-5y=38

y=38/-5

y=-7+3/5

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