2(y-6)+8=3(3-y)

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Solution for 2(y-6)+8=3(3-y) equation: 



2(y-6)+8=3(3-y)

We move all terms to the left:

2(y-6)+8-(3(3-y))=0

We add all the numbers together, and all the variables

2(y-6)-(3(-1y+3))+8=0

We multiply parentheses

2y-(3(-1y+3))-12+8=0



We calculate terms in parentheses: -(3(-1y+3)), so:

3(-1y+3)

We multiply parentheses

-3y+9

Back to the equation:

-(-3y+9)



We add all the numbers together, and all the variables

2y-(-3y+9)-4=0

We get rid of parentheses

2y+3y-9-4=0

We add all the numbers together, and all the variables

5y-13=0

We move all terms containing y to the left, all other terms to the right

5y=13

y=13/5

y=2+3/5

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