2(y-6)-4=-2(-9y+1)-8y

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Solution for 2(y-6)-4=-2(-9y+1)-8y equation: 



2(y-6)-4=-2(-9y+1)-8y

We move all terms to the left:

2(y-6)-4-(-2(-9y+1)-8y)=0

We multiply parentheses

2y-(-2(-9y+1)-8y)-12-4=0



We calculate terms in parentheses: -(-2(-9y+1)-8y), so:

-2(-9y+1)-8y

We add all the numbers together, and all the variables

-8y-2(-9y+1)

We multiply parentheses

-8y+18y-2

We add all the numbers together, and all the variables

10y-2

Back to the equation:

-(10y-2)



We add all the numbers together, and all the variables

2y-(10y-2)-16=0

We get rid of parentheses

2y-10y+2-16=0

We add all the numbers together, and all the variables

-8y-14=0

We move all terms containing y to the left, all other terms to the right

-8y=14

y=14/-8

y=-1+3/4

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