2(y-6)-4y=-3(4+6y)-4

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Solution for 2(y-6)-4y=-3(4+6y)-4 equation: 



2(y-6)-4y=-3(4+6y)-4

We move all terms to the left:

2(y-6)-4y-(-3(4+6y)-4)=0

We add all the numbers together, and all the variables

2(y-6)-4y-(-3(6y+4)-4)=0

We add all the numbers together, and all the variables

-4y+2(y-6)-(-3(6y+4)-4)=0

We multiply parentheses

-4y+2y-(-3(6y+4)-4)-12=0



We calculate terms in parentheses: -(-3(6y+4)-4), so:

-3(6y+4)-4

We multiply parentheses

-18y-12-4

We add all the numbers together, and all the variables

-18y-16

Back to the equation:

-(-18y-16)



We add all the numbers together, and all the variables

-2y-(-18y-16)-12=0

We get rid of parentheses

-2y+18y+16-12=0

We add all the numbers together, and all the variables

16y+4=0

We move all terms containing y to the left, all other terms to the right

16y=-4

y=-4/16

y=-1/4

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