2(y-6)-5=-3(-4y+5)-2y

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Solution for 2(y-6)-5=-3(-4y+5)-2y equation: 



2(y-6)-5=-3(-4y+5)-2y

We move all terms to the left:

2(y-6)-5-(-3(-4y+5)-2y)=0

We multiply parentheses

2y-(-3(-4y+5)-2y)-12-5=0



We calculate terms in parentheses: -(-3(-4y+5)-2y), so:

-3(-4y+5)-2y

We add all the numbers together, and all the variables

-2y-3(-4y+5)

We multiply parentheses

-2y+12y-15

We add all the numbers together, and all the variables

10y-15

Back to the equation:

-(10y-15)



We add all the numbers together, and all the variables

2y-(10y-15)-17=0

We get rid of parentheses

2y-10y+15-17=0

We add all the numbers together, and all the variables

-8y-2=0

We move all terms containing y to the left, all other terms to the right

-8y=2

y=2/-8

y=-1/4

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