2(y-6)2y=-32

Solution for 2(y-6)2y=-32 equation:

2(y-6)2y=-32

We move all terms to the left:

2(y-6)2y-(-32)=0

We add all the numbers together, and all the variables

2(y-6)2y+32=0

We multiply parentheses

4y^2-24y+32=0

a = 4; b = -24; c = +32;
Δ = b2-4ac
Δ = -242-4·4·32
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8}{2*4}=\frac{16}{8}
=2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8}{2*4}=\frac{32}{8}
=4
$