2(y-6)=(y-4)-y

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Solution for 2(y-6)=(y-4)-y equation: 



2(y-6)=(y-4)-y

We move all terms to the left:

2(y-6)-((y-4)-y)=0

We multiply parentheses

2y-((y-4)-y)-12=0



We calculate terms in parentheses: -((y-4)-y), so:

(y-4)-y

We add all the numbers together, and all the variables

-1y+(y-4)

We get rid of parentheses

-1y+y-4

We add all the numbers together, and all the variables

-4

Back to the equation:

-(-4)



We add all the numbers together, and all the variables

2y-8=0

We move all terms containing y to the left, all other terms to the right

2y=8

y=8/2

y=4

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