2(y-6)=3(y-4)-6

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Solution for 2(y-6)=3(y-4)-6 equation: 



2(y-6)=3(y-4)-6

We move all terms to the left:

2(y-6)-(3(y-4)-6)=0

We multiply parentheses

2y-(3(y-4)-6)-12=0



We calculate terms in parentheses: -(3(y-4)-6), so:

3(y-4)-6

We multiply parentheses

3y-12-6

We add all the numbers together, and all the variables

3y-18

Back to the equation:

-(3y-18)



We get rid of parentheses

2y-3y+18-12=0

We add all the numbers together, and all the variables

-1y+6=0

We move all terms containing y to the left, all other terms to the right

-y=-6

y=-6/-1

y=+6

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