2(y-6)=3(y-4)-y

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Solution for 2(y-6)=3(y-4)-y equation:



2(y-6)=3(y-4)-y
We move all terms to the left:
2(y-6)-(3(y-4)-y)=0
We multiply parentheses
2y-(3(y-4)-y)-12=0
We calculate terms in parentheses: -(3(y-4)-y), so:
3(y-4)-y
We add all the numbers together, and all the variables
-1y+3(y-4)
We multiply parentheses
-1y+3y-12
We add all the numbers together, and all the variables
2y-12
Back to the equation:
-(2y-12)
We get rid of parentheses
2y-2y+12-12=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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