2(y-7)-4=-3(-8y+5)-4y

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Solution for 2(y-7)-4=-3(-8y+5)-4y equation:



2(y-7)-4=-3(-8y+5)-4y
We move all terms to the left:
2(y-7)-4-(-3(-8y+5)-4y)=0
We multiply parentheses
2y-(-3(-8y+5)-4y)-14-4=0
We calculate terms in parentheses: -(-3(-8y+5)-4y), so:
-3(-8y+5)-4y
We add all the numbers together, and all the variables
-4y-3(-8y+5)
We multiply parentheses
-4y+24y-15
We add all the numbers together, and all the variables
20y-15
Back to the equation:
-(20y-15)
We add all the numbers together, and all the variables
2y-(20y-15)-18=0
We get rid of parentheses
2y-20y+15-18=0
We add all the numbers together, and all the variables
-18y-3=0
We move all terms containing y to the left, all other terms to the right
-18y=3
y=3/-18
y=-1/6

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