2(y-7)-4=-4(4y+3)-2y

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Solution for 2(y-7)-4=-4(4y+3)-2y equation: 



2(y-7)-4=-4(4y+3)-2y

We move all terms to the left:

2(y-7)-4-(-4(4y+3)-2y)=0

We multiply parentheses

2y-(-4(4y+3)-2y)-14-4=0



We calculate terms in parentheses: -(-4(4y+3)-2y), so:

-4(4y+3)-2y

We add all the numbers together, and all the variables

-2y-4(4y+3)

We multiply parentheses

-2y-16y-12

We add all the numbers together, and all the variables

-18y-12

Back to the equation:

-(-18y-12)



We add all the numbers together, and all the variables

2y-(-18y-12)-18=0

We get rid of parentheses

2y+18y+12-18=0

We add all the numbers together, and all the variables

20y-6=0

We move all terms containing y to the left, all other terms to the right

20y=6

y=6/20

y=3/10

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