2(y-8)-1=-3(-8y+3)-8y

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Solution for 2(y-8)-1=-3(-8y+3)-8y equation: 



2(y-8)-1=-3(-8y+3)-8y

We move all terms to the left:

2(y-8)-1-(-3(-8y+3)-8y)=0

We multiply parentheses

2y-(-3(-8y+3)-8y)-16-1=0



We calculate terms in parentheses: -(-3(-8y+3)-8y), so:

-3(-8y+3)-8y

We add all the numbers together, and all the variables

-8y-3(-8y+3)

We multiply parentheses

-8y+24y-9

We add all the numbers together, and all the variables

16y-9

Back to the equation:

-(16y-9)



We add all the numbers together, and all the variables

2y-(16y-9)-17=0

We get rid of parentheses

2y-16y+9-17=0

We add all the numbers together, and all the variables

-14y-8=0

We move all terms containing y to the left, all other terms to the right

-14y=8

y=8/-14

y=-4/7

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