2(y-8)-5=-3(-9y+3)-7y

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Solution for 2(y-8)-5=-3(-9y+3)-7y equation: 



2(y-8)-5=-3(-9y+3)-7y

We move all terms to the left:

2(y-8)-5-(-3(-9y+3)-7y)=0

We multiply parentheses

2y-(-3(-9y+3)-7y)-16-5=0



We calculate terms in parentheses: -(-3(-9y+3)-7y), so:

-3(-9y+3)-7y

We add all the numbers together, and all the variables

-7y-3(-9y+3)

We multiply parentheses

-7y+27y-9

We add all the numbers together, and all the variables

20y-9

Back to the equation:

-(20y-9)



We add all the numbers together, and all the variables

2y-(20y-9)-21=0

We get rid of parentheses

2y-20y+9-21=0

We add all the numbers together, and all the variables

-18y-12=0

We move all terms containing y to the left, all other terms to the right

-18y=12

y=12/-18

y=-2/3

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