2(y-8)=4(y+1)-30

Solution for 2(y-8)=4(y+1)-30 equation:

2(y-8)=4(y+1)-30

We move all terms to the left:

2(y-8)-(4(y+1)-30)=0

We multiply parentheses

2y-(4(y+1)-30)-16=0


We calculate terms in parentheses: -(4(y+1)-30), so:

4(y+1)-30

We multiply parentheses

4y+4-30

We add all the numbers together, and all the variables

4y-26

Back to the equation:

-(4y-26)


We get rid of parentheses

2y-4y+26-16=0

We add all the numbers together, and all the variables

-2y+10=0

We move all terms containing y to the left, all other terms to the right

-2y=-10

y=-10/-2

y=+5