2(z+1)-(5z-4)=

Solution for 2(z+1)-(5z-4)= equation:

Simplifying
2(z + 1) + -1(5z + -4) = 0

Reorder the terms:
2(1 + z) + -1(5z + -4) = 0
(1 * 2 + z * 2) + -1(5z + -4) = 0
(2 + 2z) + -1(5z + -4) = 0

Reorder the terms:
2 + 2z + -1(-4 + 5z) = 0
2 + 2z + (-4 * -1 + 5z * -1) = 0
2 + 2z + (4 + -5z) = 0

Reorder the terms:
2 + 4 + 2z + -5z = 0

Combine like terms: 2 + 4 = 6
6 + 2z + -5z = 0

Combine like terms: 2z + -5z = -3z
6 + -3z = 0

Solving
6 + -3z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -3z = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -3z = 0 + -6
-3z = 0 + -6

Combine like terms: 0 + -6 = -6
-3z = -6

Divide each side by '-3'.
z = 2

Simplifying
z = 2