2(z+1)-3(4z-2)=2(4-5z)

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Solution for 2(z+1)-3(4z-2)=2(4-5z) equation: 


Simplifying
2(z + 1) + -3(4z + -2) = 2(4 + -5z)

Reorder the terms:
2(1 + z) + -3(4z + -2) = 2(4 + -5z)
(1 * 2 + z * 2) + -3(4z + -2) = 2(4 + -5z)
(2 + 2z) + -3(4z + -2) = 2(4 + -5z)

Reorder the terms:
2 + 2z + -3(-2 + 4z) = 2(4 + -5z)
2 + 2z + (-2 * -3 + 4z * -3) = 2(4 + -5z)
2 + 2z + (6 + -12z) = 2(4 + -5z)

Reorder the terms:
2 + 6 + 2z + -12z = 2(4 + -5z)

Combine like terms: 2 + 6 = 8
8 + 2z + -12z = 2(4 + -5z)

Combine like terms: 2z + -12z = -10z
8 + -10z = 2(4 + -5z)
8 + -10z = (4 * 2 + -5z * 2)
8 + -10z = (8 + -10z)

Add '-8' to each side of the equation.
8 + -8 + -10z = 8 + -8 + -10z

Combine like terms: 8 + -8 = 0
0 + -10z = 8 + -8 + -10z
-10z = 8 + -8 + -10z

Combine like terms: 8 + -8 = 0
-10z = 0 + -10z
-10z = -10z

Add '10z' to each side of the equation.
-10z + 10z = -10z + 10z

Combine like terms: -10z + 10z = 0
0 = -10z + 10z

Combine like terms: -10z + 10z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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