2(z+1)-4(2-4)=2(z+5)

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Solution for 2(z+1)-4(2-4)=2(z+5) equation: 


Simplifying
2(z + 1) + -4(2 + -4) = 2(z + 5)

Reorder the terms:
2(1 + z) + -4(2 + -4) = 2(z + 5)
(1 * 2 + z * 2) + -4(2 + -4) = 2(z + 5)
(2 + 2z) + -4(2 + -4) = 2(z + 5)

Combine like terms: 2 + -4 = -2
2 + 2z + -4(-2) = 2(z + 5)

Multiply -4 * -2
2 + 2z + 8 = 2(z + 5)

Reorder the terms:
2 + 8 + 2z = 2(z + 5)

Combine like terms: 2 + 8 = 10
10 + 2z = 2(z + 5)

Reorder the terms:
10 + 2z = 2(5 + z)
10 + 2z = (5 * 2 + z * 2)
10 + 2z = (10 + 2z)

Add '-10' to each side of the equation.
10 + -10 + 2z = 10 + -10 + 2z

Combine like terms: 10 + -10 = 0
0 + 2z = 10 + -10 + 2z
2z = 10 + -10 + 2z

Combine like terms: 10 + -10 = 0
2z = 0 + 2z
2z = 2z

Add '-2z' to each side of the equation.
2z + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 2z + -2z

Combine like terms: 2z + -2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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