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2(z+1)-4(z-4)=2(z+5
We move all terms to the left:
2(z+1)-4(z-4)-(2(z+5)=0
We multiply parentheses
2z-4z-(2(z+5)+2+16=0
We add all the numbers together, and all the variables
-2z-(2(z+5)+2+16=0
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