2(z+1)-4(z-4)=2(z+5)

Solution for 2(z+1)-4(z-4)=2(z+5) equation:

Simplifying
2(z + 1) + -4(z + -4) = 2(z + 5)

Reorder the terms:
2(1 + z) + -4(z + -4) = 2(z + 5)
(1 * 2 + z * 2) + -4(z + -4) = 2(z + 5)
(2 + 2z) + -4(z + -4) = 2(z + 5)

Reorder the terms:
2 + 2z + -4(-4 + z) = 2(z + 5)
2 + 2z + (-4 * -4 + z * -4) = 2(z + 5)
2 + 2z + (16 + -4z) = 2(z + 5)

Reorder the terms:
2 + 16 + 2z + -4z = 2(z + 5)

Combine like terms: 2 + 16 = 18
18 + 2z + -4z = 2(z + 5)

Combine like terms: 2z + -4z = -2z
18 + -2z = 2(z + 5)

Reorder the terms:
18 + -2z = 2(5 + z)
18 + -2z = (5 * 2 + z * 2)
18 + -2z = (10 + 2z)

Solving
18 + -2z = 10 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
18 + -2z + -2z = 10 + 2z + -2z

Combine like terms: -2z + -2z = -4z
18 + -4z = 10 + 2z + -2z

Combine like terms: 2z + -2z = 0
18 + -4z = 10 + 0
18 + -4z = 10

Add '-18' to each side of the equation.
18 + -18 + -4z = 10 + -18

Combine like terms: 18 + -18 = 0
0 + -4z = 10 + -18
-4z = 10 + -18

Combine like terms: 10 + -18 = -8
-4z = -8

Divide each side by '-4'.
z = 2

Simplifying
z = 2