2(z+1)=-4(z-4)

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Solution for 2(z+1)=-4(z-4) equation: 



2(z+1)=-4(z-4)

We move all terms to the left:

2(z+1)-(-4(z-4))=0

We multiply parentheses

2z-(-4(z-4))+2=0



We calculate terms in parentheses: -(-4(z-4)), so:

-4(z-4)

We multiply parentheses

-4z+16

Back to the equation:

-(-4z+16)



We get rid of parentheses

2z+4z-16+2=0

We add all the numbers together, and all the variables

6z-14=0

We move all terms containing z to the left, all other terms to the right

6z=14

z=14/6

z=2+1/3

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