2(z+1)=3(z+4)

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Solution for 2(z+1)=3(z+4) equation: 



2(z+1)=3(z+4)

We move all terms to the left:

2(z+1)-(3(z+4))=0

We multiply parentheses

2z-(3(z+4))+2=0



We calculate terms in parentheses: -(3(z+4)), so:

3(z+4)

We multiply parentheses

3z+12

Back to the equation:

-(3z+12)



We get rid of parentheses

2z-3z-12+2=0

We add all the numbers together, and all the variables

-1z-10=0

We move all terms containing z to the left, all other terms to the right

-z=10

z=10/-1

z=-10

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