2(z+1)=3(z+4)

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Solution for 2(z+1)=3(z+4) equation:



2(z+1)=3(z+4)
We move all terms to the left:
2(z+1)-(3(z+4))=0
We multiply parentheses
2z-(3(z+4))+2=0
We calculate terms in parentheses: -(3(z+4)), so:
3(z+4)
We multiply parentheses
3z+12
Back to the equation:
-(3z+12)
We get rid of parentheses
2z-3z-12+2=0
We add all the numbers together, and all the variables
-1z-10=0
We move all terms containing z to the left, all other terms to the right
-z=10
z=10/-1
z=-10

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