2(z+1)=4z+14

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Solution for 2(z+1)=4z+14 equation:


Simplifying
2(z + 1) = 4z + 14

Reorder the terms:
2(1 + z) = 4z + 14
(1 * 2 + z * 2) = 4z + 14
(2 + 2z) = 4z + 14

Reorder the terms:
2 + 2z = 14 + 4z

Solving
2 + 2z = 14 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
2 + 2z + -4z = 14 + 4z + -4z

Combine like terms: 2z + -4z = -2z
2 + -2z = 14 + 4z + -4z

Combine like terms: 4z + -4z = 0
2 + -2z = 14 + 0
2 + -2z = 14

Add '-2' to each side of the equation.
2 + -2 + -2z = 14 + -2

Combine like terms: 2 + -2 = 0
0 + -2z = 14 + -2
-2z = 14 + -2

Combine like terms: 14 + -2 = 12
-2z = 12

Divide each side by '-2'.
z = -6

Simplifying
z = -6

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