2(z+1)=5(z-2);7

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Solution for 2(z+1)=5(z-2);7 equation: 



2(z+1)=5(z-2)7

We move all terms to the left:

2(z+1)-(5(z-2)7)=0

We multiply parentheses

2z-(5(z-2)7)+2=0



We calculate terms in parentheses: -(5(z-2)7), so:

5(z-2)7

We multiply parentheses

35z-70

Back to the equation:

-(35z-70)



We get rid of parentheses

2z-35z+70+2=0

We add all the numbers together, and all the variables

-33z+72=0

We move all terms containing z to the left, all other terms to the right

-33z=-72

z=-72/-33

z=2+2/11

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