2(z+2)+4z=28

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Solution for 2(z+2)+4z=28 equation:


2(z+2)+4z=28

We simplify the equation to the form, which is simple to understand 
2(z+2)+4z=28

Reorder the terms in parentheses
+(+2z+4)+4z=28

Remove unnecessary parentheses
+2z+4+4z=+28

We move all terms containing z to the left and all other terms to the right. 
+2z+4z=+28-4

We simplify left and right side of the equation. 
+6z=+24

We divide both sides of the equation by 6 to get z. 
z=4

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