2(z+2)-2(2z+5)=18

Solution for 2(z+2)-2(2z+5)=18 equation:

Simplifying
2(z + 2) + -2(2z + 5) = 18

Reorder the terms:
2(2 + z) + -2(2z + 5) = 18
(2 * 2 + z * 2) + -2(2z + 5) = 18
(4 + 2z) + -2(2z + 5) = 18

Reorder the terms:
4 + 2z + -2(5 + 2z) = 18
4 + 2z + (5 * -2 + 2z * -2) = 18
4 + 2z + (-10 + -4z) = 18

Reorder the terms:
4 + -10 + 2z + -4z = 18

Combine like terms: 4 + -10 = -6
-6 + 2z + -4z = 18

Combine like terms: 2z + -4z = -2z
-6 + -2z = 18

Solving
-6 + -2z = 18

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -2z = 18 + 6

Combine like terms: -6 + 6 = 0
0 + -2z = 18 + 6
-2z = 18 + 6

Combine like terms: 18 + 6 = 24
-2z = 24

Divide each side by '-2'.
z = -12

Simplifying
z = -12